(2x-3)(x-n)=2x^2+5x+m求m与n

求和x+x^2+x^3+…x^n= (-x^2n-2)*(-x)^5÷[x^n+1*x^n*(-x)]=? (-x)^3x^n-1+x^2n(-x)^3 已知集合P={x|x=2n,n∈N^+},集合Q={x|x=3n,n∈N*}.则P∩Q等于多少?,A,{x|x=n,n∈N*}B.{x|x=5n,n∈N*}C,{x|x=12n,n∈N*}D,{x|x=6n,n∈N*} C语言 f(x)=1+x+x^2/2!+x^3/3!+...+x^n/n!直到|x^n/n| (2x-3)(x-n)=2x^2+5x+m求m与n sn=(x-1)+(x^2-3)+(x^3-5)+...+[x^n-(2n-1)] 2x^n+2-8x^n=?x^5-x^3=? 求Sn=3x+4x²+5x³+.+（n+2）x^n (4x^n-2x^n-1-3x^n+2)÷（-5x^n-1) x^n-1(3x^n+4x^n+1-5x^n+2) *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || x^n*x^n+1*(-x)^2n*x+(-x)^2n+3x^2n-2*x f(x)=x(x-1)(x-2)(x-3).(x-n),则f(x)的n+1阶求导 求和：Sn=1+3x+5x*x+7x*x*x+……+（2n-1)x^n-1 (x不为0和1） 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 求和：Sn=1-3x+5x^2-7x^3+.+(2n+1)(-x)^n(n属于N*) 为什么x+x^3+x^5+…+x^(2n+1)+…=x/(1-x^2)?