甲乙两车分别从A,B两地出发,相向而行.甲 乙 两车分别从A、B两地出发相向而行.出发时.甲、乙的速度比是5;4,相遇后,,乙的速度提高 25% ,这样,当甲到达B地时.乙离A地还有15千米.那么A.B两地相距

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甲乙两车分别从A,B两地出发,相向而行.甲 乙 两车分别从A、B两地出发相向而行.出发时.甲、乙的速度比是5;4,相遇后,,乙的速度提高 25% ,这样,当甲到达B地时.乙离A地还有15千米.那么A.B两地相距

甲乙两车分别从A,B两地出发,相向而行.甲 乙 两车分别从A、B两地出发相向而行.出发时.甲、乙的速度比是5;4,相遇后,,乙的速度提高 25% ,这样,当甲到达B地时.乙离A地还有15千米.那么A.B两地相距
甲乙两车分别从A,B两地出发,相向而行.
甲 乙 两车分别从A、B两地出发相向而行.出发时.甲、乙的速度比是5;4,相遇后,,乙的速度提高 25% ,这样,当甲到达B地时.乙离A地还有15千米.那么A.B两地相距多少?

甲乙两车分别从A,B两地出发,相向而行.甲 乙 两车分别从A、B两地出发相向而行.出发时.甲、乙的速度比是5;4,相遇后,,乙的速度提高 25% ,这样,当甲到达B地时.乙离A地还有15千米.那么A.B两地相距
81千米
假设甲,乙速度:5V,4V 全程9Vt
15/(1Vt-4Vt/9 / 5V(1+20%)*4V(1+25%)) = 81

有时间吗? 33.75吧

81KM

设速度为W,则甲车为5W,乙车为4W。
5W·120%=4W·125%+15
(5·120%)W=(4·125%)W+15
6W=5W+15
W=15
则A地到B的距离为:
5·15·120%=90Km 或(4·15·125%=90Km)
答:AB两地相距90千米。

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设甲速度为5A乙速度为4A;相遇时用了时间为H;所以相遇后甲速度为6A乙速度为5A;相遇后到甲到B地用时为4AH/6A;所以得15千米=5AH-5A(4AH/6A)可得AH=9千米;AB两地相距为5AH+4AH=9AH;所以相距为81千米。

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