化简求值:1/2ln(2x+2√(x^2-1))+ln(√(x+1)-√(x-1)) 2x

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化简求值:1/2ln(2x+2√(x^2-1))+ln(√(x+1)-√(x-1)) 2x

化简求值:1/2ln(2x+2√(x^2-1))+ln(√(x+1)-√(x-1)) 2x
化简求值:1/2ln(2x+2√(x^2-1))+ln(√(x+1)-√(x-1)) 2x

化简求值:1/2ln(2x+2√(x^2-1))+ln(√(x+1)-√(x-1)) 2x
=1/2ln(x+1+x-1+2√(x^2-1))+ln(√(x+1)-√(x-1))
=ln(√(x+1)+√(x-1)) +ln(√(x+1)-√(x-1))
=ln[(x+1)-(x-1)]
=ln2

1/2ln(2x+2√(x^2-1))+ln(√(x+1)-√(x-1))
=1/2ln(2x+2√(x^2-1))+1/2ln(√(x+1)-√(x-1))^2
=1/2ln(2x+2√(x^2-1))+1/2ln((x+1)+(x-1)-2√((x+1)(x-1)))
=1/2ln(2x+2√(x^2-1))+1/2ln(2x-2√(x^2-1))
=1/2l...

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1/2ln(2x+2√(x^2-1))+ln(√(x+1)-√(x-1))
=1/2ln(2x+2√(x^2-1))+1/2ln(√(x+1)-√(x-1))^2
=1/2ln(2x+2√(x^2-1))+1/2ln((x+1)+(x-1)-2√((x+1)(x-1)))
=1/2ln(2x+2√(x^2-1))+1/2ln(2x-2√(x^2-1))
=1/2ln[(2x+2√(x^2-1))(2x-2√(x^2-1))]
=1/2ln[(2x)^2-4(x^2-1))]
=1/2ln4
=ln2
答案好像不是你所说的ln2x啊

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