若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
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若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
7y(x-3y)²-2(3y-x)³=7y(x-3y)²+2(x-3y)³=(x-3y)²[7y+2(x-3y)=(x-3y)²(7y+2X-6y)
=(x-3y)²(2x+y)
因为 2x+y=6,x-3y=1
所以 原式=1²*6=6
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