COS八分之π的6次方减去SIN八分之π的6次方

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 12:36:01
COS八分之π的6次方减去SIN八分之π的6次方

COS八分之π的6次方减去SIN八分之π的6次方
COS八分之π的6次方减去SIN八分之π的6次方

COS八分之π的6次方减去SIN八分之π的6次方
我选择了直接计算.
公式cos2θ=2cos²θ-1可以用cos2θ表示出cosθ
所以cos²八分之派=(1+cos四分之派)/2=(2+√2)/4
故sin²θ=1-cos²θ=(2-√2)/4
原式=(cos²八分之派)³-(sin²八分之派)³
=(7√2)/16

COS八分之π的6次方减去SIN八分之π的6次方
=(cos³π/8+sin³π/8)(cos³π/8-sin³π/8)
=(cosπ/8+sinπ/8)(cos²π/8-cosπ/8sinπ/8+sin²π/8)(cosπ/8-sinπ/8)(cos²π/8+cosπ/8sinπ/8+sin²π/8)...

全部展开

COS八分之π的6次方减去SIN八分之π的6次方
=(cos³π/8+sin³π/8)(cos³π/8-sin³π/8)
=(cosπ/8+sinπ/8)(cos²π/8-cosπ/8sinπ/8+sin²π/8)(cosπ/8-sinπ/8)(cos²π/8+cosπ/8sinπ/8+sin²π/8)(立方差,立方和公式)
=(cosπ/8+sinπ/8)(cosπ/8-sinπ/8)(1-cosπ/8sinπ/8)(1+cosπ/8sinπ/8)
=(cos²π/8-sin²π/8)[1-(1/2sinπ/4)²]
=cosπ/4(1-1/4sin²π/4)
=√2/2(1-1/4*1/2)
=√2/2*7/8=7√2/16(不懂问我)

收起