称次品时：2-3个要1次,4-9个要2次,10-27个要3次,28-81要4次,82-243个要5次,问6-10个各要几次?llllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllll

来源：学生作业帮助网编辑：作业帮时间：2024/05/07 03:40:49

称次品时：2-3个要1次,4-9个要2次,10-27个要3次,28-81要4次,82-243个要5次,问6-10个各要几次?llllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllll
称次品时：2-3个要1次,4-9个要2次,10-27个要3次,28-81要4次,82-243个要5次,问6-10个各要几次?
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称次品时：2-3个要1次,4-9个要2次,10-27个要3次,28-81要4次,82-243个要5次,问6-10个各要几次?llllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllll 用天平找次品,当只含1个次品时,知道次品重或轻,则所测物品数目与测试的次数关系为:3个物品,保证能找出次品要测（）次；4~9个物品,保证能找出次品需测（）次；10~27个物品,保证能找出次找次品2个至3个要1次保证找出,4个至9个要2次保证找出,10个至27个要3次保证找出,28个至81个要4次保证找出,82个至243个要5次保证找出,接下来是什么,它有什么规律已知次品比正品轻或重有九个外形完全相同的皮球,其中一个是次品,比正品轻一些,用天平称至少几次才可以把次品找出来?1.如果每次拿2个2个称,至少要称（）次.2.如果每次拿3个3个称,至少要称（）次.3.如果每次找次品的规律就是介个：3 1次 9 2次 10~27 3次 28~81 4次 82~242 5次 ..就是介个的规律啦 81个零件,1个次品(较轻)天平称4次,请用图表示! 一个工人生产了81个同样的零件,有一个是次品,它比其它零件轻.你能称3次保证把它找出来吗?怎么称?81个至少要称4次啊,怎么用3次称?还要保证找出次品. 25个零件其中一个是次品用天平称3次找出次品!如果称4次的就不用了 ↑ 用天平找次品：2到3个要一次,4到9个要二次,10到27个要三次,28到81个要4次,82-242要5次有虾米规律?为什么有12个乒乓球有一个是次品,能不能2次用天平称出来? 有8个玻璃球,从外观看都一样,其中有1个是次品,次品比正品要轻些,最少称2次可以找出次品,请问怎样称? 如何求出用天平找次品的需要次数如2-3的要1次请大家告诉用算式怎么求6的要2次请大家告诉我怎么求的！次品有4~6个要2次次品是轻的！我的意思是怎么求这个！比如什么乘以什么得到这个 12个螺丝一个次品不知轻重称3次称出来 14：10堆机器零件,每堆10个,其中九堆全是正品,一堆全是次品,机器零件的形状都一样,如果正品每个重800克,次品每个重801克,那么要找到那堆次品至少称（）次.15：由1,2,3组成五位数,要求这五位 8个外观相同的的球中有一个次品（次品比正品轻）,至少要用天平称（）次才能保证找到次品. 一桶羽毛球有12个其中一个是次品用天平称至少要称（）次一定能找到次品? 有8个重量相等的零件,混杂着一个较轻的次品,用天平称2次如何称出这个次品? 有6个零件,知道有1个是次品,他比正品要轻一点,其他5个正品零件都一样重你能用天平称的办法,最多称2次,就知道哪一个是次品零件吗?为什么?用这个格式:╱平衡6（2 2 2 ） ╲不平衡快