float f=123.456; printf("%10.2f,%-10.1f\n",f,f);中的-10.1怎么解释

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float f=123.456; printf(

float f=123.456; printf("%10.2f,%-10.1f\n",f,f);中的-10.1怎么解释
float f=123.456; printf("%10.2f,%-10.1f\n",f,f);中的-10.1怎么解释

float f=123.456; printf("%10.2f,%-10.1f\n",f,f);中的-10.1怎么解释
-10.1表示输出有一位小数的10位数(包括小数点),且左对齐,不足位数时 右补空格

#include void main() { float a,b,t; scanf( %f,%f,&a,&b); if(a>b) { t=a; a=b; b=t; } pri#includevoid main(){float a,b,t;scanf( %f,%f,&a,&b);if(a>b){t=a;a=b;b=t;}printf(%f,%f ,a,b);}为什么输入负数 输出的全是乱七八糟的饿 float f=123.456; printf(%10.2f,%-10.1f ,f,f);中的-10.1怎么解释 C语言程序:判断ax^2+bx+c=0的方程有几个解,如果有则输出,系数a,b,c由键盘输入.下面是我编写的,错在哪里?#include#includevoid main(){float a,b,c;printf(plese input a,b,c: );scanf(%f,%f,%f,&a,&b,&c);if(b*b-4*a*c>0)pri integral(float(*f)(float a,float 怎么会出现这些啊 'a' :not in formal parameter list 'b' :not in formal parameter//将a,b,c从大到小的顺序输出.#includeint main()float a,b,c,t;scanf(%f,%f,%f,&a,&b,&c);if(a>b){t=a;a=b;b=t;}if(a>c){t=a;a=c;c=t;}if(b>c){t=b;b=c;c=t;}pri 下列语句定义pf为指向float类型变量f的指针,__B___是正确的.B.float f,*pf = &f;下列语句定义pf为指向float类型变量f的指针,__B___是正确的.A.float f,*pf = f; B.float f,*pf = &f;C.float *pf = &f,f; D.float f,*pf 求x^3-15x^2+16x-80一个实根,下面程序怎么算不出来#include#includefloat f(float x){return ((x-5)*x-16)*x-80;}float xpoint(float x1,float x2){return (x1*f(x2)-x2*f(x1))/(f(x2)-f(x1));}float root(float x1,float x2){float x,y,y1;y1=f(x1);do{ float a1=2.0f,后面这个'f'表示意义? float f1 = 2.2f; float f2 = 2.2; f1 f2 各等于什么 麻烦给讲讲这道题有以下程序float f1(float n){ return n*n; }float f2(float n){ return 2*n; }main(){ float (*p1)(float),(*p2)(float),(*t)(float),y1,y2;p1=f1; p2=f2;y1=p2( p1(2.0) );t = p1; p1=p2; p2 = t;y2=p2( p1(2.0) ); printf(%3.0f,%3.0f 解方程x *x *x - 5.0 *x *x + 16.0 *x - 80.0 下面是程序,谁给我讲讲原理啊#include #include float f(float x){float y;y = x *x *x - 5.0 *x *x + 16.0 *x - 80.0;return y; }float xpoint(float x1,float x2){float y;y = (x1 *f(x2) -x2 *f(x1))/(f int main() { float a=1.0f; cout C语言:下面的功能是计算函数F(x,y,z)=(x+y)*(x+y)+(x+y)*(x-y)的值并输出.float f(float,float);main(){float x,y,z,sum;scanf(%f%f%f,&x&y&z);sum=_____________;printf(sum=%f' ,sum);}float f(float a, 编写由三角形三边求面积的函数.#includefloat kig(float x, float y,float z);main(){ float s,a,b,c; scanf(%f%f%f,&a,&b,&c); s=kig(a,b,c); printf(s=%f ,kig(a,b,c));}float kig(float x,float y,float z){ float p; p=1/4*(2*x*z+y*y-x*x-z*z); 关于定积分~错哪儿了?急~# include # define N 100# define F(x) (x)*(x)*(x)float sab(float a,float b){ float h,sum=0; scanf(%f%f,&a,&b); h=(b-a)/N; for(;a c语言的问题,求x^3-5x^2+16x-80的根,我用的弦截法,但是出错#include#includefloat f(float x){float y;y=x*(x*x-5*x+16)-80;return y;}float xpoint(float x1,float x2){float root;root=(f(x2)*x1-x2*f(x1))/(f(x2)-f(x1));return root;}void main() (int)(x*1000+0.5)/(float)1000里的(int)和(float)是什么意思啊?float x=5.16894的话,print(%f,+上面的表达式)怎么运算? C语言课后题,调用3个函数求2次方程的根,编写程序如下:#include#includemain(){void zero(float a,float b);void left();void right(float a,float b,float c);float a,b,c,d;printf(请输入a,b,c的值: );scanf(%f%f%f,&a,&b,&c);d=b