先化简再求值:亲们谁给画个图啊,我看不懂呃……就照着我那样,平方,分子分母都写一下~

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先化简再求值:亲们谁给画个图啊,我看不懂呃……就照着我那样,平方,分子分母都写一下~

先化简再求值:亲们谁给画个图啊,我看不懂呃……就照着我那样,平方,分子分母都写一下~
先化简再求值:
亲们谁给画个图啊,我看不懂呃……就照着我那样,平方,分子分母都写一下~

先化简再求值:亲们谁给画个图啊,我看不懂呃……就照着我那样,平方,分子分母都写一下~
括号里通分,{[(a-2)(a+2)]/[a(a+2)^2]-[(a-1)a]/[a(a+2)^2]}*(a-4)/(a+2)=(a^2-4-a^2+a)/[a(a+2)^2]*(a-4)/(a+2)=1/(a^2+2)
因为a^2+2a-1=0,所以a^2+2a=1,所以上式等于1

原式=[(a-2)/(a+2)*a-(a-1)/(a+2)^2]*(a+2)/(a-4)
=[(a-2)/a-(a-1)/(a+2)]*1/(a-4)
=[(a-2)(a+2)-(a-1)*a]/(a-4)*(a+2)*a
=[a^2-4-a^2+a]/(a-4)*(a+2)*a
=[a-4]/(a-4)*(a+2)*a
=1/a(a+2)
=1

=((a-2)(a+2)-a(a-1))/a(a+2)^2/((a-4)/(a+2))
=(a-4)/a(a+2)^2/(a-4)*(a+2)
=1/a(a+2)
=1/(a^2+2a)
=1/1=1

={(a-2)/a(a+2)-(a-1)/(a+2)~2} / {(a-4)/(a+2)}
={(a+2)(a-2) / a(a+2)~2 - a(a-1) / a(a+2)~2} / {(a-4)/(a+2)}
={(a~2-4-a~2+a) / a(a+2)~2 }/ {(a-4)/(a+2)}
=(a-4) / a(a+2)~2 * (a+2)/(a-4)
=1/ {a(a+2)}
=1