作业帮若有理数a.b满足丨a-6丨+（b-7)²=0试求ab/1+(a+1)(b+1)/1+(a+2)(b+2)/1.+(a+100)(b+100)/1的值
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若有理数a.b满足丨a-6丨+（b-7)²=0试求ab/1+(a+1)(b+1)/1+(a+2)(b+2)/1.+(a+100)(b+100)/1的值
若有理数a.b满足丨a-6丨+（b-7)²=0试求ab/1+(a+1)(b+1)/1+(a+2)(b+2)/1.+(a+100)(b+100)/1的值
若有理数a.b满足丨a-6丨+（b-7)²=0试求ab/1+(a+1)(b+1)/1+(a+2)(b+2)/1.+(a+100)(b+100)/1的值
丨a-6丨+（b-7)²=0
所以a-6=0 b-7=0
a=6 b=7
ab/1+(a+1)(b+1)/1+(a+2)(b+2)/1.+(a+100)(b+100)/1
=1/6-1/7+1/7-1/8+……+1/106-1/107
=1/6-1/107
=101/642
642分之101
丨a-6丨=0，a=6.
（b-7)²=0,b=7,
所以1/ab+1/(a+1)(b+1)+1/（a+2)(b+2）+……1/(a+100)(b+100)
=1/6-1/7+1/7-1/8+1/8-1/9+……+1/106－1/107
＝1/6－1/107
＝101/642.
估计是你把分数颠倒了吧！不然的话可不容易计算出来。
a=6,b=7,则原式=6*7/1+7*8/1+8*9/1+......+106*107/1=(6/1-7/1)+(7/1-8/1)+(8/1-9/1)+......+(106/1-107/1)=6/1-107/1=642/101
丨a-6丨+（b-7)²=0
所以a-6=0 b-7=0
a=6 b=7
ab/1+(a+1)(b+1)/1+(a+2)(b+2)/1...........+(a+100)(b+100)/1
=1/6-1/7+1/7-1/8+……+1/106-1/107
=1/6-1/107
=101/642
642分之101