y''(e^x+1)+y'=0 y''=(y')^3+y' 自学高数中,感激不尽

y''(e^x+1)+y'=0 y''=(y')^3+y' 自学高数中,感激不尽 f(x,y)=e^-y,0 y'=1/(e^y+x)通解 y'e^(x-y)=1通解? 微分方程通解（1+e^(x/y))dx+e^(x/y)(1-x/y)dy=0 常微分方程的通解dy/dx=(x-y+1)/(x+y-3)y^4=2y^n+y=0y''+6y'+9y=e^(-3x)y''+y'-2y=4e^(2x) [e^(x+y)-e^x]dx+[e^(x+y)-e^y]dy=0求通解 y=y(x)由方程 [e^(x+y)]+sin(xy)=1确定,求y'(x)及y'(0) (y/x)y'+e^y=0的通解, 求微分方程通解 (y/x)y'+e^y=0 y^3+(x+2)e^y=1 y''(-2) 微积分方程求解e^x + (e^x cot y + 2y csc y)y' = 0 e^(x+y)-xy=1,求y''(0) y''(e^x+1)+y'=0的通解 y=1/x^2(x>0) y=(1-x)/(1+x) y=(e^x-e^-x)/2 1、y’=(xy+y)/(x+xy),y(1)=1 2、(y/x)y’+e^y=0,y(1)=0 求解微分方程, y'-2y=(e^x)-x 设e^Y + XY =e 确定函数y=y（x）求Y''(0).