若实数X`Y`Z满足x+(1/y)=4,y+(1/z)=1,z+(1/x)=7/3求xyz的值/为除号

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若实数X`Y`Z满足x+(1/y)=4,y+(1/z)=1,z+(1/x)=7/3求xyz的值/为除号

若实数X`Y`Z满足x+(1/y)=4,y+(1/z)=1,z+(1/x)=7/3求xyz的值/为除号
若实数X`Y`Z满足x+(1/y)=4,y+(1/z)=1,z+(1/x)=7/3求xyz的值
/为除号

若实数X`Y`Z满足x+(1/y)=4,y+(1/z)=1,z+(1/x)=7/3求xyz的值/为除号
三式相乘等到:
[x+(1/y)]*[y+(1/z)]*[z+(1/x)]=xyz+y+1/z++x+1/y+z+1/x+1/xyz
=xyz+1/xyz+4+1+7/3
=4*1*7/3
即xyz+1/xyz=2 两边同乘xyz,
得到(xyz)(xyz)-2xyz+1=0
所以xyz=1