lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2 lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2解释下为什么同除以x^2,还有第二步=lim x→∞ (1/x²-1)/(2-3/x^2) 怎么算出来等于-1/

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/16 16:59:17
lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2 lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2解释下为什么同除以x^2,还有第二步=lim x→∞ (1/x²-1)/(2-3/x^2) 怎么算出来等于-1/

lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2 lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2解释下为什么同除以x^2,还有第二步=lim x→∞ (1/x²-1)/(2-3/x^2) 怎么算出来等于-1/
lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2
lim x→∞ (1-x^2)/(2x^2-3)
=lim x→∞ (1/x²-1)/(2-3/x^2)
=-1/2
解释下为什么同除以x^2,
还有第二步
=lim x→∞ (1/x²-1)/(2-3/x^2)
怎么算出来等于-1/2的
我想起来怎么算了，我好关闭问题

lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2 lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2解释下为什么同除以x^2,还有第二步=lim x→∞ (1/x²-1)/(2-3/x^2) 怎么算出来等于-1/
- - 楼主很给力.

Lim [x^2/(x^2-1)]^x (x→∞) lim(1+x/x)2x (x→∞) lim(x)lim(x→∞) [(x-1)/(x+1)]^2x 为什么 lim(x->∞) {[(-2)/(x+1)]*2x} = -4 x/2-1lim(1-2/x)x→∞ lim(x→∞)(1-2/x)^2x lim(x→∞)(1-2/x) (x+1)次方 lim(x→∞)[1+(1/x)]^x/2 lim x→∞(2x+1)/(3x-4) lim x→∞ x-1/x^2 lim x→∞(1-2/x)^x= 求lim(√x^2+1)-x x→-∞ 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 lim xsin(2/x) x→∞ lim x→1 x-1/x^2-x lim(x→0)e^x-x-1/x^2 lim(x→∞)[(X^2+2x+5)/(3x^2-x+1) = lim(x→∞)(4x^3+2x-1)/(2x^3-3x+1) lim(x→∞)(2x^3-x^2-3)/(x^3-x+1)