(1)6x n+1 -14x n +8x n-1 (2)(x+1)(x+2)(x+3)(x+4)+1 (3)(1-a 2 )(1-b 2 )-4ab (4)8a 3 -b 3 (5)3x 2 +5xy-2y 2 +x+9y-4 (6)2x 2 +xy-y 2 -4x+5y-6 (7)x 2 +x-(a 2 -a)

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(1)6x n+1 -14x n +8x n-1 (2)(x+1)(x+2)(x+3)(x+4)+1 (3)(1-a 2 )(1-b 2 )-4ab (4)8a 3 -b 3 (5)3x 2 +5xy-2y 2 +x+9y-4 (6)2x 2 +xy-y 2 -4x+5y-6 (7)x 2 +x-(a 2 -a)
(1)6x n+1 -14x n +8x n-1 (2)(x+1)(x+2)(x+3)(x+4)+1 (3)(1-a 2 )(1-b 2 )-4ab (4)8a 3 -b 3 (5)3x 2 +5xy-2y 2 +x+9y-4 (6)2x 2 +xy-y 2 -4x+5y-6 (7)x 2 +x-(a 2 -a)

(1)6x n+1 -14x n +8x n-1 (2)(x+1)(x+2)(x+3)(x+4)+1 (3)(1-a 2 )(1-b 2 )-4ab (4)8a 3 -b 3 (5)3x 2 +5xy-2y 2 +x+9y-4 (6)2x 2 +xy-y 2 -4x+5y-6 (7)x 2 +x-(a 2 -a)
（1）6x n+1 -14x n +8x n-1=2x^(n-1)[3x^2-7x+4]=2x^(n-1)(x-1)(3x-4) （2）(x+1)(x+2)(x+3)(x+4)+1=[(x+1)(x+4)][(x+2)(x+3)]+1 =[(x^2+5x)+4][(x^2+5x)+6]+1 =(x^2+5x)^2+10(x^2+5x)+25 =(x^2+5x+5)^2 (3)(1-a 2 )(1-b 2 )-4ab=(ab)^2-(a^2+b^2)+1-4ab=[(ab)^2-2ab+1]-[a^2+b^2+2ab] =(ab-1)^2-(a+b)^2 =(ab-1+a+b)(ab-1-a-b) （4）8a^3-b^3=(2a)^3-b^3=(2a-b)(4a^2+2ab+b^2) (5)3x^2+5xy-2y^2+x+9y-4=(3x^2+5xy-2y^2)+x+9y-4 =(3x-y)(x+2y)+4(x+2y)-(3x-y)-4 =(3x-y+4)(x+2y-1) (6)2x^2+xy-y^2-4x+5y-6=(2x^2+xy-y^2)-4x+5y-6=(x+y)(2x-y)+2(x+y)-3(2x-y)-6 =[(x+y)-3][(2x-y)+2]=(x+y-3)(2x-y+2) (7)x^2+x-(a^2-a)=(x^2-a^2)+(x+a)=(x-a)(x+a)+(x+a)=(x+a)(x-a+1)

6x^n+1-14x^n+8x^n-1因式分解 x^(n)*x^(n+1)+x^(2n)*x 因式分解4x^(n+2)-9x^n+6x^(n-1)-x^(n-2) 因式分解4x^n+2-9x^n+6x^n-1-x^n-2 因式分解-6x^n+8x^n-1 因式分解2x^n-6x^n-1-8x^n-2 f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n 6x的n+1次方-14x的n次方+8x的n-1次方因式分解 6x的n+1次方-14x的n次方+8x的n-1次方,急求答案若(x^2+1/x)^n(n∈N+,n 因式分解：(x^n+1)+(2x^n)+(x^n-1) x^n+1-2x^n+x^n-1因式分解 x^n-1-2x^n+x^n-1因式分解分解因式x^n-x^(n-1)+x^(n-2) x^n-2x^n+1,因式分解 x^n*x^n+1*(-x)^2n*x+(-x)^2n+3x^2n-2*x (8x^n+1-3x^n-1)-2(-x+9x^n+1-4x^n)= 约分(x^n+2)+(x^n+1)-6x^n/(2x^n+1)+5x^n-(3x^n-1)