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来源：学生作业帮助网编辑：作业帮时间：2024/05/02 11:48:35

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因为x 趋于0时极限存在,而分子极限为0,所以分母肯定也是趋于0的,所以f(x),x趋于0极限为-1,又f(x)连续,所以f(0)=—1.
原式=lim[f(x)+1+sinx/x-1]/x=[f(x)+1]/x+(sinx/x-1)/x,第一项是f(x)在0点的导数的定义,后一项可以用罗比达法则求出极限为0,所以f'(0)=2.

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