1/(x+1)+2/(x-1)=4/(x2-1)

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1/(x+1)+2/(x-1)=4/(x2-1)

1/(x+1)+2/(x-1)=4/(x2-1)
1/(x+1)+2/(x-1)=4/(x2-1)

1/(x+1)+2/(x-1)=4/(x2-1)
1/(x+1)+2/(x-1)=4/(x+1)(x-1)
两边乘(x+1)(x-1)
x-1+2(x+1)=4
x-1+2x+2=4
3x=3
x=1
经检验,x=1,分母x-1=0,增根,舍去
所以方程无解

1/(x+1)+2/(x-1)=4/(x²-1)
两边同时乘以x²-1,得
x-1+2(x+1)=4
则3x=3
解得x=1
检验:将x=1代入原方程,分母为0,分式无意义,所以x=1是增根
所以原方程无解

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