1-3+5-7+·····+(-1)^(2n-1) *(4n-1)怎么计算呢?

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1-3+5-7+·····+(-1)^(2n-1) *(4n-1)怎么计算呢?

1-3+5-7+·····+(-1)^(2n-1) *(4n-1)怎么计算呢?
1-3+5-7+·····+(-1)^(2n-1) *(4n-1)怎么计算呢?

1-3+5-7+·····+(-1)^(2n-1) *(4n-1)怎么计算呢?
题有问题:(-1)^(2n-1) *(4n-1)通项的话,每一项都应该是负的.
请检查原题,纠正错误.
非要做的话,看这样行不?
由于 (-1)^(2n-1)是-1的奇次方,其值为 -1,那么,和式的最后一项为 -(4n-1)
这也说明一共有2n项(偶数项)求和.把原式1、2项结合,3、4项结合,5、6项结合,
…… 最后两项结合,共得到n个括号,每个括号的和都是 -2,故所求和为 -2n.
我们若不把最后一项看成“通项”,而看成最后一个加数,倒也能说通,但不符合
数学的常用表示法.

啊啊

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