作业帮七年级的分式计算[(x+2)/2x][(x^3-3x^2)\(x^2+5x+6)]\[(x^3-9x)\(x^2+2x-3)][(x^2-4y^2)/(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/14 19:58:53
![七年级的分式计算[(x+2)/2x][(x^3-3x^2)\(x^2+5x+6)]\[(x^3-9x)\(x^2+2x-3)][(x^2-4y^2)/(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]](/uploads/image/z/8684649-9-9.jpg?t=%E4%B8%83%E5%B9%B4%E7%BA%A7%E7%9A%84%E5%88%86%E5%BC%8F%E8%AE%A1%E7%AE%97%5B%28x%2B2%29%2F2x%5D%5B%28x%5E3-3x%5E2%29%5C%28x%5E2%2B5x%2B6%29%5D%5C%5B%28x%5E3-9x%29%5C%28x%5E2%2B2x-3%29%5D%5B%28x%5E2-4y%5E2%29%2F%28x%2By%29%5D%2F%28x%5E2-2xy%29%2F%5B%28x%5E2%2Bxy-2y%5E2%29%5C%28x%5E2-y%5E2%29%5D)
七年级的分式计算[(x+2)/2x][(x^3-3x^2)\(x^2+5x+6)]\[(x^3-9x)\(x^2+2x-3)][(x^2-4y^2)/(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
七年级的分式计算
[(x+2)/2x][(x^3-3x^2)\(x^2+5x+6)]\[(x^3-9x)\(x^2+2x-3)]
[(x^2-4y^2)/(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
七年级的分式计算[(x+2)/2x][(x^3-3x^2)\(x^2+5x+6)]\[(x^3-9x)\(x^2+2x-3)][(x^2-4y^2)/(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
1.
原式={[(x+2)/2x][x^2(x-3)/(x+2)(x+3)]}/{x(x+3)(x-3)/(x+3)(x-1)}
=[(x+2)(x-3)(x+3)(x-1)x^2]/[2x^2(x+2)(x+3)(x+3)(x-3)]
=(x-1)/2(x+3)
2.
原式=[(x+2y)(x-2y)(x+y)(x-y)]/[(x+y)(x-2y)(x+2y)(x-y)x^2]
=1/x^2