作业帮先化简再求值[1/（x²+4x+4）+1/x²+2x]÷（x+1）/(x+2),其中x=3先化简再求值[1/（x²+4x+4）+1/x²+2x]÷（x+1）/(x+2)其中x=3今天圣诞节,也祝各位圣诞快乐
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/13 14:22:22
![先化简再求值[1/（x²+4x+4）+1/x²+2x]÷（x+1）/(x+2),其中x=3先化简再求值[1/（x²+4x+4）+1/x²+2x]÷（x+1）/(x+2)其中x=3今天圣诞节,也祝各位圣诞快乐](/uploads/image/z/758253-21-3.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%E5%86%8D%E6%B1%82%E5%80%BC%5B1%2F%EF%BC%88x%26%23178%3B%2B4x%2B4%EF%BC%89%2B1%2Fx%26%23178%3B%2B2x%5D%C3%B7%EF%BC%88x%2B1%EF%BC%89%2F%28x%2B2%29%2C%E5%85%B6%E4%B8%ADx%3D3%E5%85%88%E5%8C%96%E7%AE%80%E5%86%8D%E6%B1%82%E5%80%BC%5B1%2F%EF%BC%88x%26%23178%3B%2B4x%2B4%EF%BC%89%2B1%2Fx%26%23178%3B%2B2x%5D%C3%B7%EF%BC%88x%2B1%EF%BC%89%2F%28x%2B2%29%E5%85%B6%E4%B8%ADx%3D3%E4%BB%8A%E5%A4%A9%E5%9C%A3%E8%AF%9E%E8%8A%82%2C%E4%B9%9F%E7%A5%9D%E5%90%84%E4%BD%8D%E5%9C%A3%E8%AF%9E%E5%BF%AB%E4%B9%90)
先化简再求值[1/（x²+4x+4）+1/x²+2x]÷（x+1）/(x+2),其中x=3先化简再求值[1/（x²+4x+4）+1/x²+2x]÷（x+1）/(x+2)其中x=3今天圣诞节,也祝各位圣诞快乐
先化简再求值[1/（x²+4x+4）+1/x²+2x]÷（x+1）/(x+2),其中x=3
先化简再求值
[1/（x²+4x+4）+1/x²+2x]÷（x+1）/(x+2)
其中x=3
今天圣诞节,也祝各位圣诞快乐
先化简再求值[1/（x²+4x+4）+1/x²+2x]÷（x+1）/(x+2),其中x=3先化简再求值[1/（x²+4x+4）+1/x²+2x]÷（x+1）/(x+2)其中x=3今天圣诞节,也祝各位圣诞快乐
[1/(x²+4x+4)+1/(x²+2x)]÷(x+1)/(x+2)
=[1/(x+2)²+1/x(x+2)]÷(x+1)/(x+2)
=[1/(x+2)+1/x]÷(x+1)
=[(x+x+2)/x(x+2)]÷(x+1)
=2(x+1)/x(x+2)÷(x+1)
=2/x(x+2)
=2/[3*(3+2)]
=2/15
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