函数y=y(x)由方程x^3-3xy^2+2y^3-32=0,且f(x)求导,试求f(x)的极值//解的对吗?两边对x求导:3x^2-3y^2-6xyy'+6y^2y'=0得y'=(y^2-x^2)/[2(y^2-xy)]=(y+x)/(2y)令y'=0,得y+x=0,将y=-x代入原方程:x^3-3x^3-2x^3-32=0,得x^3=-8即x=-2,y=

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函数y=y(x)由方程x^3-3xy^2+2y^3-32=0,且f(x)求导,试求f(x)的极值//解的对吗?两边对x求导:3x^2-3y^2-6xyy'+6y^2y'=0得y'=(y^2-x^2)/[2(y^2-xy)]=(y+x)/(2y)令y'=0,得y+x=0,将y=-x代入原方程:x^3-3x^3-2x^3-32=0,得x^3=-8即x=-2,y=

函数y=y(x)由方程x^3-3xy^2+2y^3-32=0,且f(x)求导,试求f(x)的极值//解的对吗?两边对x求导:3x^2-3y^2-6xyy'+6y^2y'=0得y'=(y^2-x^2)/[2(y^2-xy)]=(y+x)/(2y)令y'=0,得y+x=0,将y=-x代入原方程:x^3-3x^3-2x^3-32=0,得x^3=-8即x=-2,y=
函数y=y(x)由方程x^3-3xy^2+2y^3-32=0,且f(x)求导,试求f(x)的极值//解的对吗?
两边对x求导:
3x^2-3y^2-6xyy'+6y^2y'=0
得y'=(y^2-x^2)/[2(y^2-xy)]=(y+x)/(2y)
令y'=0,得y+x=0,
将y=-x代入原方程:x^3-3x^3-2x^3-32=0,
得x^3=-8
即x=-2,
y=2
即极值点为(-2,2)
在x=-2的左边邻域,y'

函数y=y(x)由方程x^3-3xy^2+2y^3-32=0,且f(x)求导,试求f(x)的极值//解的对吗?两边对x求导:3x^2-3y^2-6xyy'+6y^2y'=0得y'=(y^2-x^2)/[2(y^2-xy)]=(y+x)/(2y)令y'=0,得y+x=0,将y=-x代入原方程:x^3-3x^3-2x^3-32=0,得x^3=-8即x=-2,y=
你作的很正确!

正确的,是这样的啊!

135/099876=88k97uji