(1) b/(a-b) + a/(a+b)-2ab/(b^2-a^2)(2) [1-1/(1-X) ] ÷X/X-1

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 12:03:12
(1) b/(a-b) + a/(a+b)-2ab/(b^2-a^2)(2) [1-1/(1-X) ] ÷X/X-1

(1) b/(a-b) + a/(a+b)-2ab/(b^2-a^2)(2) [1-1/(1-X) ] ÷X/X-1
(1) b/(a-b) + a/(a+b)-2ab/(b^2-a^2)
(2) [1-1/(1-X) ] ÷X/X-1

(1) b/(a-b) + a/(a+b)-2ab/(b^2-a^2)(2) [1-1/(1-X) ] ÷X/X-1
(1) b/(a-b) + a/(a+b)-2ab/(b^2-a^2)
=(a+b)b/(a^2-b^2)+(a-b)a/(a^2-b^2)+2ab/(a^2-b^2)
=(ab+b^2+a^2-ab+2ab)/(a^2-b^2)
=(a^2+2ab+b^2)/(a^2-b^2)
=(a+b)^2/(a+b)(a-b)
=(a+b)/(a-b)
(2) [1-1/(1-X) ] ÷X/X-1
=(1-x-1)/(1-x)*(x-1)/x
=(-x)/(1-x)*(x-1)/x
=x/(x-1)*(x-1)/x
=1

1, (a+b)/(a-b)
2, 1

求解吗?第一题(a+b)^2/(a^2-b^2)
第二题1/(X-1)

1 原式=(a+b)b/a^2-b^2+(a-b)a/a^2-b^2+2ab/a^2-b^2
=a^2+2ab+b^2/(a+b)(a-b)
=(a+b)/(a-b)
2 原式=1-1/(1-x)-1
=1/(1-x) [X不等于0或1]