设 {an }是等差数列,{bn } =(1/2 )的an次方且b1 +b2+b3=21/8,b1*b1*b3=1/8,求an

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 18:54:10
设 {an }是等差数列,{bn } =(1/2 )的an次方且b1 +b2+b3=21/8,b1*b1*b3=1/8,求an

设 {an }是等差数列,{bn } =(1/2 )的an次方且b1 +b2+b3=21/8,b1*b1*b3=1/8,求an
设 {an }是等差数列,{bn } =(1/2 )的an次方且b1 +b2+b3=21/8,b1*b1*b3=1/8,求an

设 {an }是等差数列,{bn } =(1/2 )的an次方且b1 +b2+b3=21/8,b1*b1*b3=1/8,求an
设公差为d
(1/2)^(a1+a2+a3)=1/8
a1+a2+a3=3
a2=1
b2=1/2
b1+b2+b3=21/8
(1/2)^(1-d)+(1/2)^(1+d)=17/8
解得d=2,a1=-1
∴an=2n-3

如果数列{an}是等差数列,设bn=(1/2)^an,数列{bn}是等比数列吗? 设数列an,bn满足:bn=(a1+a2+a3+a4+...+an)/n,若bn是等差数列,求证an也是等差数列 等差数列求和 难题设{An}是等差数列,求证:以bn=a1+a2+...an/n (n属于N+)为通项公式的数列{bn}是等差数列 设{an}是等差数列,{bn}是等比数列,且0 设{an}是等差数列,an=2n-1,{bn}是等比数列,bn=2^(n-1)求{an/bn}前n项和Sn 设an是等差数列,求证以bn=(a1+a2+a3+…+an)/n,n属于N+为通项公式的数列bn是等差数列 一道求证等差数列题目,a1=1 ,an=2a(n-1)+ 2^(n-1) 设bn= an/2^(n-1) 求证bn是等差数列 求证等差数列,a1=1 ,an=2a(n-1)+ 2^(n-1) 设bn= an/2^(n-1) 求证bn是等差数列 如何证明:已知数列{an}是等差数列,设bn=2an+3a(n+1).求证:数列{bn}也是等差数列. 设数列{an}为等差数列,求证bn=(a1+a2+...+an)/n(n属于正整数)为通项公式的数列{bn}是等差数列 设数列{bn}为等差数列,求证bn=(a1+a2+...+an)/n(n属于正整数)为通项公式的数列{an}是等差数列 an+1^2-a^2=bn an是等差数列 求证bn是等差数列 已知数列{an}是等差数列,且bn=an+a(n-1),求证bn也是等差数列 设Bn=A1+A2+...+An/n,若{an}等差数列,且公差为d,问{Bn}是否为等差数列 设{an}是等差数列,bn=1/2^an,已知b1+b2+b3=21/8,b1*b2*b3=1/8,求等差数列的通项an? 设{an}是等差数列,bn=1/2^an,已知b1+b2+b3=21/8,b1*b2*b3=1/8,求等差数列的通项an? 设Tn为数列{an}的前n项之积,满足Tn=1-an(N属于正整数)【1】设bn=1/an,证明数列{bn}是等差数列,并求an和bn. a1=1,an+1=2an+2^n 设bn=an/2^n-1 1证明bn是等差数列 2求an前n项和sna1=1,an+1=2an+2^n 设bn=an/2^n-1 1.证明bn是等差数列 2.求an前n项和sn