(4a+2b-1)(4a-2b+1）(4a+2b-1)^2-(4a-2b+1)^2两个算式,各等于多少?

(4a+2b-1)(4a-2b+1）(4a+2b-1)^2-(4a-2b+1)^2两个算式,各等于多少?
(4a+2b-1)(4a-2b+1）(4a+2b-1)^2-(4a-2b+1)^2
两个算式,各等于多少?

(4a+2b-1)(4a-2b+1）(4a+2b-1)^2-(4a-2b+1)^2两个算式,各等于多少?
(4a+2b-1)(4a-2b+1)
=[4a+(2b-1)][4a-(2b-1)]
=(4a)^2-(2b-1)^2
=16a^2-4b^2+4b-1
(4a+2b-1)^2-(4a-2b+1)^2
=[(4a+2b-1)+(4a-2b+1)][(4a+2b-1)-(4a-2b+1)]
=(8a)(4b-2)
=32ab-16a

(4a+2b-1)(4a-2b+1
=[4a+(2b-1)][4a-(2b-1)]
=(4a)²-(2b-1)²
=4a²-(4b²-4b+1)
=4a²-4b²+4b-1
(4a+2b-1)²-(4a-2b+1)²
=[(4a+2b-1)+(4a-2b+1)][(4a+2b-1)-(4a-2b+1)]
=(8a)(4b-2)
=32ab-16a