1.{ 3x-y+z=3 { 2x+y+3=11 {x+y+z=12 求高手解答这是三元一次方程

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1.{ 3x-y+z=3 { 2x+y+3=11 {x+y+z=12 求高手解答这是三元一次方程

1.{ 3x-y+z=3 { 2x+y+3=11 {x+y+z=12 求高手解答这是三元一次方程
1.{ 3x-y+z=3 { 2x+y+3=11 {x+y+z=12 求高手解答
这是三元一次方程

1.{ 3x-y+z=3 { 2x+y+3=11 {x+y+z=12 求高手解答这是三元一次方程
.{ 3x-y+z=3 ,2x+y+3=11 ,x+y+z=12
2x+y+3=11 ,得y=11-3-2x,y=8-2x
x+y+z=12 ,得x+8-2x+z=12 ,x=z-4
3x-y+z=3 ,得3x-(8-2x)+z=3,3x-8+2x+z=3,5x+z=11,z=11-5x
5x+z=11,代入x=z-4,得5z-20+z=11,6z=31,z=31/6
x=z-4,代入z=11-5x,得6x=7,x=7/6
3x-y+z=3,代入z=31/6和x=7/6,得21/6-y+31/6=3,
y=(21+31)/6-3,y=26/3-9/3=(26-9)/3,得y=17/3
最后得到:{x=7/6,z=31/6,y=17/3

先把1式和3式相减 得4式 2x-2y=-9
2式就等于 2x+y=8
2式减去4式得3y=-1 y=-(1/3)
把y=-(1/3)代近2式 得 x=25/6
把 y=-(1/3) x=25/6代进式3
得 z=49/6

孩子,第二个方程会不会错了啊?应该是2x+y+3Z=11吧

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