解不等式:(1/5)^[ (log2 X)^2-1] < (1/5)^[ 2x(2+log底数为根号2 X)

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解不等式:(1/5)^[ (log2 X)^2-1] < (1/5)^[ 2x(2+log底数为根号2 X)

解不等式:(1/5)^[ (log2 X)^2-1] < (1/5)^[ 2x(2+log底数为根号2 X)
解不等式:(1/5)^[ (log2 X)^2-1] < (1/5)^[ 2x(2+log底数为根号2 X)

解不等式:(1/5)^[ (log2 X)^2-1] < (1/5)^[ 2x(2+log底数为根号2 X)
(1/5)^[ (log2 X)^2-1] < (1/5)^[ 2x(2+log底数为根号2 X)
=> (log2 X)^2-1 > 2x(2+log底数为根号2 X),
令log2 X = y
=>y^2 -1 > 4 + 2( log2X/log2根号2)
=> y^2 > 5 + 4y => y> 5 => x > 32