作业帮已知[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求（4x/4x²-y²）-（1/2x+y）的值/是分数线
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![已知[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求（4x/4x²-y²）-（1/2x+y）的值/是分数线](/uploads/image/z/1333331-35-1.jpg?t=%E5%B7%B2%E7%9F%A5%5B%28x%26%23178%3B%2By%26%23178%3B%29-%28x-y%29%26%23178%3B%2B2y%28x-y%29%5D%C3%B74y%3D1%2C%E6%B1%82%EF%BC%884x%2F4x%26%23178%3B-y%26%23178%3B%EF%BC%89-%EF%BC%881%2F2x%2By%EF%BC%89%E7%9A%84%E5%80%BC%2F%E6%98%AF%E5%88%86%E6%95%B0%E7%BA%BF)
已知[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求（4x/4x²-y²）-（1/2x+y）的值/是分数线
已知[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求（4x/4x²-y²）-（1/2x+y）的值
/是分数线
已知[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求（4x/4x²-y²）-（1/2x+y）的值/是分数线
条件里括号展开,因为y不为0,所以条件可得：2x-y=2,
（4x/4x²-y²）-（1/2x+y）应该是4x/(4x²-y²)-1/(2x+y)=(4x-2x+y)/((2x+y)*(2x-y))=1/(2x-y)=1/2