∫π/2到-π/2√cosx-cosx^3dx=

∫π/2到-π/2√cosx-cosx^3dx=
∫π/2到-π/2√cosx-cosx^3dx=

∫π/2到-π/2√cosx-cosx^3dx=
∫π/2到-π/2√cosx-cosx^3dx
=-2∫(0,π/2)√cosx（1-cos²x）dx
=-2∫(0,π/2)sinx√cosxdx
=2∫(0,π/2)√cosxdcosx
=2*(2/3)(cosx)^(3/2)|(0,π/2)
=-4/3